Which Nernst equation is true to find out the potential of non-standard electrochemical cell from the following?
$F e (s) | F e^{2 +} (x M) | | I^{-} (a q .) | I_{2} (s) (P t)$

E_{c e l l} = E_{c e l l}^{\circ} - \frac{0.592}{n} {log}_{10} [F e^{2 +}] [I^{-}]^{2}

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E_{c e l l} = E_{c e l l}^{\circ} - \frac{0.0592}{n} {log}_{10} [F e^{2 +}] [I^{-}]^{2}

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E_{c e l l} = E_{c e l l}^{\circ} - \frac{0.0592}{n} {log}_{10} [F e^{2 +}] [I^{-}]

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E_{c e l l} = E_{c e l l}^{\circ} - \frac{0.0592}{n} {log}_{10} \frac{[F e^{2 +}] [I^{-}]^{2}}{[F e] [I_{2}]}

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Solution

The correct option is A $E_{c e l l} = E_{c e l l}^{\circ} - \frac{0.0592}{n} {log}_{10} [F e^{2 +}] [I^{-}]^{2}$
According to the given cell we have
$F e + I_{2} \to F e^{2 +} + 2 I^{-}$
so, we have,
$E_{c e l l} = E_{c e l l}^{0} - \frac{0.0591}{n} l o g_{10} [F e^{2 +}] [I^{-}]^{2}$

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Similar questions

E_{c e l l}

F e_{(} s) | F e^{2 +} (0.1 M) | | F e^{3 +} (0.01 M) | F e^{2 +} (1 M) | P t

E_{F e^{3 +} / F e^{2 +}}^{0} = + 0.771 V, E_{F e^{2 +} / F e}^{0} = - 0.41 V

Z n^{2 +} + 2 e^{-} \to Z n; E = - 0.76 V

F e^{2 +} + 2 e^{-} \to F e; E = - 0.44 V

F e^{2 +} = Z n^{-} \to Z n^{2 +} + F e

E_{C r^{3 +} / C r}^{\circ} = - 0.72 V, E_{F e^{2 +} / F e}^{\circ} = - 0.42 V

C r | C r^{3 +} (0.1 M) | | F e^{2 +} (0.01 M) | F e

E_{C r^{3 +} / C r}^{\circ} = - 0.72, E_{F e^{2 +} / F e}^{\circ} = - 0.42 V

C r | C r^{3 +} (0.1 M) | | F e^{2 +} (0.01 M) | F e

Electra has trouble finding the correct Nernst equation for the cell $Z n (s) | Z n^{2 +} | | C u^{2 +} | C u (s) a t 25^{\circ} C$
Can you help her?

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