Which odd number needs to be taken out to form a cube number?
$21 + 23 + 29 + 27 + 19 + 25$

21

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19

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23

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25

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Solution

The correct option is B $19$
We know,
$1 = 1 = 1^{3}$ ,
$3 + 5 = 8 = 2^{3}$ ,
$7 + 9 + 11 = 27 = 3^{3}$ ,
$13 + 15 + 17 + 19 = 64 = 4^{3}$ ,
$21 + 23 + 25 + 27 + 29 = 125 = 5^{3}$ .
Therefore, $19$ must be taken out to form a cube number, $5^{3} = 125$ .
Hence, option $B$ is correct.

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Similar questions

Given below are marks obtained by $20$ students in Math out of $25$ .

$21, 23, 19, 17, 12, 15, 15, 17, 17, 19, 23, 23, 21, 23, 25, 25, 21, 19, 19, 19$

Prepare a frequency distribution table for the given data.

(13 - 21), (19 - 27), (15 - 23), (16 - 24)

5 + 7 + 9 + 11

$x$	$19$	$21$	$23$	$25$	$27$	$29$	$31$
$f$	$13$	$15$	$16$	$18$	$16$	$15$	$13$

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