Which of following equation has 2 as root?

x^{2} - 5 x + 8 = 0

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{4 x}^{2} - 9 x - 3 = 0

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{4 x}^{2} + 8 x - 39 = 0

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x^{2} + 6 x - 16 = 0

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Solution

The correct option is C $x^{2} + 6 x - 16 = 0$
$x^{2} + 6 x - 16 = 0$
$x^{2} + 8 x - 2 x - 16 = 0$
$(x + 8) (x - 2) = 0$
$x = 2, - 8$

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