CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Preparation of Benzene and Homologues

Which of foll...

Question

Which of following is most reactive towards nucleophilic substituting reaction

A

C H_{2} = C H - C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

C_{6} H_{5} - C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

C H_{3} C H = C H C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

C l C H_{2} - C H = C H_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $C l C H_{2} - C H = C H_{2}$
Allylic halides ( $C H 2 = C H - C H - C l$ ) are less stable than vinyl halides ( $C H_{2} = C H_{2} - C l$ ) which is less stable than benzyl halides, due to resonance stabilization.
The nucleophilic substitution in allylic halides is more than vinyl and benzyl halides because the halide group where the nucleophile is prone to attack is not directly attached to the double bonded carbon, there by the resonance interaction is less and can be easily substituted.

Suggest Corrections

thumbs-up

0

Similar questions

\begin{matrix} C H_{3} - & C H & - C H_{2} - C l | C H_{3} \end{matrix}

\begin{matrix} C H_{3} - C H_{2} - & C H & - C l | C H_{3} \end{matrix}

which is more reactive towards

S_{N} 1

reaction and why?

Q. The decreasing order of reactivity towards electrophilic addition of the following is:
I.

C H \equiv C H

C H_{2} = C H_{2}

H_{2} C = C H - C l

H C | C l = C H | C l

Q. Consider the following three halides:
(i)

C H_{3} - C H_{2} - C l

C H_{2} = C H - C l

C_{6} H_{5} - C l

Arrange C-Cl bond length of these compounds in decreasing order.

Q. Among the given reaction which is faster & why?

M e - C | C l H - M e a l c . K O H - ---- \to C H_{3} - C H = C H_{2}

C H_{3} - C H_{2} - C H_{2} - C l a l c . K O H - ---- \to C H_{3} - C H = C H_{2}

Which are free radical reactions

$I . C H_{3} - C H = C H_{2} + H B r P e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} B r I I . C H_{3} - C H = C H_{2} + H B r \to C H_{3} - C H B r - C H_{3} I I I . C H_{3} - C H = C H_{2} + C l_{2} \to C l C H_{2} - C H = C H_{2} I V . C H_{3} - C H_{3} + C l_{2} \to C l C H_{2} - C H_{3}$

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Aromatic Compounds - Preparation

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Preparation of Benzene and Homologues

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon