Which of following points lies on the line, 2x+3y=11?
x=1, y=3
Substituting each set of the values for x and y in the line equation 2x+3y=11, we have
(i) x=1, y=3LHS=(2×1)+(3×3)=11=RHS (ii) x=0, y=5LHS=(2×0)+(3×5)=15≠RHS (iii) x=−2, y=−5LHS=(2×−2)+(3×−5)=−19≠RHS (iv) x=9, y=1LHS=(2×9)+(3×1)=21≠RHS
∴x=1, y=3 lies on the line 2x+3y=11.