Question

Which of following transition will emit photons of highest frequency in Hydrogen atom ?

• A. $n=2$ to $n=1$
• B. $n=3$ to $n=2$
• C. $n=4$ to $n=3$
• D. $n=6$ to $n=4$

Answer 1

Answer: (A)

$n=2$ to $n=1$

Energy of electrons in Hydrogen atom:

$n=1:-13.6eV$

$n=2:-3.4eV$

$n=3:-1.51eV$

$n=4:-0.85eV$

$n=5:-0.54eV$

$(E_2-E_1)\to max$

According to Maxwell equation,
$E_2-E_1=hv\Rightarrow v\to max$