Which of these following equations have x=−3,y=2 as solutions?
2x+3y= 0
2x-3y=0
3x+2y=0
3x-2y=0
Substituting the values in LHS, L.H.S=2x+3y
L.H.S=2(−3)+3(2)
L.H.S=0=R.H.S
Hence x=−3,y=2 is the solution of the equation 2x+3y=0
The equation of a straight line passing through the origin and perpendicular to the straight line 2x + 3y - 7 = 0 is ______.
Find the equation of the line parallel to the line 3x+2y=8 and passing through the point (0,1).