Which of the following 0.10 m aqueous solution will have the lower freezing point?

{A l}_{2} {({S O}_{4})}_{3}

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C_{6} H_{12} O_{6}

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K I

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C_{12} H_{22} O_{11}

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Solution

The correct option is B ${A l}_{2} {({S O}_{4})}_{3}$
The depression in freezing point depends on the Van't Hoff factor.

For $A l_{2} (S O_{4})_{3},$ $i = 5$

For $C_{6} H_{12} O_{6},$ $i = 1$

For $K I,$ $i = 2$

For $C_{12} H_{22} O_{11}, 2 > i > 1$

As $A l_{2} {(S O_{4})}_{3}$ gives the maximum number of ions on dissociation, therefore it will have the lowest freezing point.

Hence, the correct option is $A$

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Similar questions

C_{12} H_{22} O_{11} + H_{2} O H^{+} - - \to C_{6} H_{12} O_{6} + C_{6} H_{12} O_{6}

C_{12} H_{22} O_{11} + H_{2} O \to C_{6} H_{12} O_{6} + C_{6} H_{12} O_{6}

2.12 \times 10^{- 4} L {m o l}^{- 1} {s e c}^{- 1}

27^{o} C

1.07 \times 10^{5} J {m o l}^{- 1}

37^{o} C

C_{12} H_{22} O_{11} + H_{2} O I n v e r t a s e - ----- \to C_{6} H_{12} O_{6} A + C_{6} H_{12} O_{6} B

C_{6} H_{12} O_{6} z y m a s e - --- \to 2 C_{2} H_{5} O H + 2 {C O}_{2}

A

B

Which of the following 0.10 M aqueous solution will have the lowest freezing point.

Of the following 0.10 m aqueous solution, which one will exhibit the largest freezing point depression?

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