Which of the following about x2+9 is true?
x2+9 cannot be split into the product of first degree factors.
Let the first degree factors as (x-a)(x-b).
Then, we have
x2+9=(x−a)(x−b)=x2−(a+b)x+ab
The above expression gives a+b=0
ab=9
We need to find "a" and "b". For that we need to find (a-b) first using the formula (a−b)2=(a+b)2−4ab
⇒(a−b)2=0−4(9)=−36
The square of no number is negative. So, there are no numbers satisfying the above pair of equations.
Thus x2+9 cannot be split into the product of first degree factors.