wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Which of the following accounts for the bond angle of 104.5o in water molecules?

A
sp3 hybrid state of oxygen
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
high electronegativity of H-atoms
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
low ionisation energy of H-atoms
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
lone pair-lone pair repulsion and lone pair-bond pair repulsions
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D lone pair-lone pair repulsion and lone pair-bond pair repulsions
Bond angles are affected by repulsions which are lplp>lpbp>bpbp.

In H2O molecule, O has 2 bond pairs and 2 lone pairs. So, the steric number is 4 and the hybridisation is sp3. Hence, the geometry is tetrahedral and the shape is bent with a bond angle of 104.5 due to lone pair-lone pair repulsion and lone pair-bond pair repulsions.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon