Question

Which of the following acidity order is correct?

• A. 1-Alkyne > Alkene > Alkane
• B. Alkene > Alkane > 1-Alkyne
• C. Alkane > Alkene > 1-Alkyne
• D. None of these

Answer 1

The correct option is A 1-Alkyne > Alkene > Alkane

$R-C\equiv CH\to R-C\equiv C^{-}$

$R-CH=C{H}_2\to R-CH=C^{-}H$

$R–C{H}_2–C{H}_3\to R–C{H}_2{C}^{-}{H}_2$

$C^{-}$ is sp hybridized i.e. it can hold negative

Carbon with triple bond has high electronegativity can hold negative charge to its most stable.

[More stable the conjugate base more acidic the compound]