Which of the following alkane cannot show isomerism?

C_{4} H_{10}

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C_{3} H_{8}

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C_{5} H_{12}

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C_{6} H_{14}

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Solution

The correct option is C $C_{3} H_{8}$

At least four carbon atoms are required for hydrocarbons to show isomerism (branching can't be done in less than 4 C-atom chain). Propane (C₃H₈) has three carbon atoms in its molecule, so it does not exhibit isomerism.

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