Which of the following aninos neutralize the acidic pH of the chyme that enters into the duodonum from the stomach?

H_{2} P O_{4}^{-}

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H S O_{4}^{-}

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H C O_{3}^{-}

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C H_{3} C O O^{-}

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Solution

The correct option is A $H_{2} P O_{4}^{-}$
Chyme has a pH of around 2 (highly acidic). Once it is in the small intestine, it stimulates the pancreas to release fluid containing a high concentration of bicarbonate ions. This fluid neutralizes the highly acidic gastric juice.
So, the correct option is 'HCO $_{3}$ $^{-}$ '.

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Similar questions

K_{a}

H S O_{4}^{-} = 1.2 \times 10^{- 2}, H_{2} P O_{4}^{-} = 6.3 \times 10^{- 8}, H C O_{3}^{-} = 4.7 \times 10^{- 11}

Identify Bronsted acids in the reaction : $H_{2} C O_{3} + H P O_{4}^{2 -} ⇌ H_{2} P O_{4}^{-} + H C O_{3}^{-}$

{N H}_{3}, {H S O}_{4}^{-}, H_{2} {S O}_{4}, {H C O}_{3}^{-}, H_{3} O

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