Which of the following applies in the reaction, $C H_{3} C H B r C H_{2} C H_{3} a l c . K O H ⟶ C H_{3} C H = C H C H_{3} (major product) + C H_{2} = C H C H_{2} C H_{3} (minor product)$

𝞫-Elimination reaction

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Saytzeff's rule

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Dehydrohalogenation

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All of the above

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Solution

The correct option is D All of the above
The given reaction is
$C H_{3} C H B r C H_{2} C H_{3} a l c . K O H ⟶ C H_{3} C H = C H C H_{3} (major product) + C H_{2} = C H C H_{2} C H_{3} (minor product)$
When alkyl halide is heated in presence of alcoholic KOH it undergo dehydrohalogenation to give highly substituted alkene as a major product according to the saytzeff rule. This reaction is a $β -$ Elimination reaction.

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Similar questions

C H_{3} C H = C H_{2}

C H_{3} C H = C H C H_{2} C H_{3}

C H_{3} C H = C H C H_{3}

C H_{3} - C H_{2} - C H_{2} - C H_{3} H_{2} S O_{4} - --- \to 475 K

D

C H_{3} - C H (C H_{3}) - C H_{2} - C H_{2} - B r a l c . K O H - ----- \to Δ A (i) C o n c . H_{2} S O_{4} - --------- \to (i i) H_{2} O / Δ B Major product + C Minor product

B H I / Δ - --- \to - H_{2} O D Major product + E Minor product

W h i c h o f f o l l o w i n g r e p r e s e n t β - h y d r o x y b u t y r a t e - c o - β - h y d r o x y v a l a r a t e ?

C H_{3} C H = C H C H_{3}

C H_{3} C H_{2} C H = C H_{2}

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