ΔTfαi×m
Higher the i(van't Hoff), more freezing point is depressed or lower is the freezing point and vice verse.
1. Fructose is non-electrolyte, i=1 and m=0.6 hence,
ΔTfα1×0.6=0.6
2. CuCl2 is electrolyte, contains 3 ions in it one copper ion and two chloride ion, i=3, m=0.3
ΔTfα3×0.3=0.9
3. Al2(SO4)3 is electrolyte, contains 5 ions in it two aluminum ion and three sulfate ion, i=5, m=0.1
ΔTfα5×0.1=0.5
4. Mg3(PO4)2 is electrolyte, contains 5 ions in it three magnesium ion and two phosphate ion, i=5, m=0.2
ΔTfα5×0.2=1.0
Hence, the lowest ΔTf is for Al2(SO4)3 and so it has the highest freezing point