Which of the following are $A p s$ ? If they form an $A P$ , find the common difference $d$ and write three more terms.
$- 10, - 6, - 2, 2.....$

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Solution

Series : $- 10, - 6, - 2, 2$
$a_{2} - a_{1} =\Rightarrow - 6 - (- 10)$
$=\Rightarrow - 6 + 10 = + 4$
$a_{3} - a_{2} = - 2 - (- 6)$
$= - 2 + 6 = + 4$
Since $a_{3} - a_{2} = a_{2} - a_{1}$
This is $A . P$ with $a_{1} = - 10, d = 4$
$∴ 3$ terms are :- $a + 4 d, a + 5 d, a + 6 d$
$\Rightarrow 6, 10, 14$

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Which of the following are Aps? If they form an AP, find the common difference d and write three more terms.−10,−6,−2,2.....

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