You visited us 1 times! Enjoying our articles? Unlock Full Access!

Distributivity

Which of the ...

Question

Which of the following are correct?

a (b+c) = b a + a c

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

b (a+c) = b a + b c

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(a+c) b = a b + c b

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

All of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
A
a (b+c) = b a + a c

B
b (a+c) = b a + b c

C
(a+c) b = a b + c b

Options (i), (ii) and (iii) are correct as they follow the distributive law.

Suggest Corrections

Similar questions

A = ∣ ∣ ∣ ∣ \begin{matrix} 1 & 1 & 1 a & b & c a^{3} & b^{3} & c^{3} \end{matrix} ∣ ∣ ∣ ∣, B = ∣ ∣ ∣ ∣ ∣ \begin{matrix} 1 & 1 & 1 a^{2} & b^{2} & c^{2} a^{3} & b^{3} & c^{3} \end{matrix} ∣ ∣ ∣ ∣ ∣, C = ∣ ∣ ∣ ∣ ∣ \begin{matrix} a & b & c a^{2} & b^{2} & c^{2} a^{3} & b^{3} & c^{3} \end{matrix} ∣ ∣ ∣ ∣ ∣,

a, b, c

{(\frac{a + c}{a - c})}^{a} < {(\frac{b + c}{b - c})}^{b}

∣ ∣ ∣ ∣ ∣ \begin{matrix} b c - a^{2} & c a - b^{2} & a b - c^{2} - b c + c a + c b & b c - c a + a b & b c + c a - a b (a + b) (a + c) & (b + c) (b + a) & (c + a) (c + b) \end{matrix} ∣ ∣ ∣ ∣ ∣ = 3 (b - c) (c - a) (a - b) (a + b + c) (b c + c a + a b)

a, b, c (a < b < c)

a + b + c = 37

\frac{1}{a} + \frac{1}{b} + \frac{1}{c} = \frac{1}{4}

\frac{a^{3} (b + c)}{(a - b) (a - c)} + \frac{b^{3} (c + a)}{(b - c) (b - a)} + \frac{a^{3} (a + b)}{(c - a) (c - b)} = b c + c a + a b

Join BYJU'S Learning Program