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Question

Which of the following are correct about the subatomic particles found in 37Cl?
i. 21 neutrons
ii. 17 protons
iii. 16 electrons

A
ii only
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B
iii only
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C
i and ii only
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D
i and iii only
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E
ii and iii only
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Solution

The correct option is A ii only
i. Atomic number of Cl is 17, so no of protons are 17.
ii. With -1 charge the no of electrons are 17+1=18.
iii. No of neutrons is (mass no - no of protons), i.e., 3717=20 neutrons.
So, only statement ii is correct.

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