Question

Which of the following are correct expression for Arrhenius equation?

• A. $A=k{e}^{-E_a/RT}$
• B. $\ln k=\ln A+\frac{E_a}{RT}$
• C. ${\log }_{10}k={\log }_{10}A-\frac{E_a}{2.303RT}$
• D. $\ln A=\ln k+\frac{E_a}{RT}$

Answer 1

Answer: (C), (D)

The correct options are
C $\ln A=\ln k+\frac{E_a}{RT}$
D ${\log }_{10}k={\log }_{10}A-\frac{E_a}{2.303RT}$

According to Arrhenius equation,

$k=A{e}^{-\frac{E_a}{RT}}$

$lnk=lnA-\frac{E_a}{RT}$

or $lnA=lnk+\frac{E_a}{RT}$

$lo{g}_{10}A=lo{g}_{10}k+\frac{E_a}{2.303RT}$