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Question

Which of the following are correct statements?
I) XAXB=0.208Δ, Δ in KJ/mole.
II) XAXB=0.1017Δ, Δ in Kcal/mole.
III) EN=(IP+EA)544, in KJ/mole.
IV) EN=(IP+EA)5.6eV.

A
I and II
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B
I, II and III
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C
III and IV
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D
II and IV
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Solution

The correct option is A III and IV
EN=(IP+EA)544, in KJ/mole.
EN=(IP+EA)5.6eV.
The given formulas are used to calculate electronegativity in the Mulliken scale. The formula can be expressed in KJ/mole as well as in eV.
Here, IP stands for ionization potential and EA is electron affinity.
For calculating electronegativity in Puling scale, we use,
XAXB=0.102ΔeV1/2
Where, XA and XB are the electronegativity of an elements A and B and Δ is the change in Bond energy.
Thus Statement III and IV are correct.

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