Question

Which of the following are equivalent fractions of $\frac{2}{3}$?

• A. $\frac{3}{6},\frac{6}{8},\frac{8}{12}$
• B. $\frac{4}{6},\frac{6}{9},\frac{8}{12}$
• C. $\frac{4}{6},\frac{6}{8},\frac{9}{12}$
• D. $\frac{2}{3},\frac{6}{8},\frac{8}{9}$

Answer 1

The correct option is B $\frac{4}{6},\frac{6}{9},\frac{8}{12}$

Let's multiply the numerator and denominator of $\frac{2}{3}$ by 2.

$\frac{2\times 2}{3\times 2}=\frac{4}{6}$

$\Rightarrow \frac{4}{6}$ is an equivalent fraction of $\frac{2}{3}.$

Similarly, on multiplying the numerator and denominator of $\frac{2}{3}$ by 3 and 4, we have

$\frac{2\times 3}{3\times 3}=\frac{6}{9}$

$\frac{2\times 4}{3\times 4}=\frac{8}{12}$

Therefore, $\frac{4}{6},\frac{6}{9}$ and $\frac{8}{12}$ are equivalent fractions of $\frac{2}{3}.$