Which of the following are factors of 54?

$27$

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$18$

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$9$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$4$

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Solution

The correct options are
A
$27$

B
$18$

C
$9$

$27 \times 2 = 54 18 \times 3 = 54 9 \times 6 = 54$

54 is not divisible by 4.

Hence, 27, 18 and 9 are factors of 54.

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54 a^{3} - 250 b^{3}

N = 3^{5} \times 5^{4} \times 6^{9} \times 7^{7} .

N

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N

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