Question

Which of the following are Lewis acid-base reactions:

• A. $Cu{Cl}_2+4H_{2}O⟶{\left[Cu{\left(H_{2}O\right)}_4\right]}^{2+}+2{Cl}^{-}$
• B. $KI+4{SO}_2\left(s\right)⟶K^{+}\left[{\left({SO}_4\right)}_4{I}^{-}\right]$
• C. ${BF}^3+{NH}_3⟶[H_{3}N\cdot {BF}_3]$
• D. ${SO}_3^{2-}+O⟶{SO}_4^{2-}$

Answer 1

Answer: (A), (B), (C), (D)

The correct options are
A $Cu{Cl}_2+4H_{2}O⟶{\left[Cu{\left(H_{2}O\right)}_4\right]}^{2+}+2{Cl}^{-}$
B $KI+4{SO}_2\left(s\right)⟶K^{+}\left[{\left({SO}_4\right)}_4{I}^{-}\right]$
C ${SO}_3^{2-}+O⟶{SO}_4^{2-}$
D ${BF}^3+{NH}_3⟶[H_{3}N\cdot {BF}_3]$

According to Lewis concept of acids and bases, an acid is a substance which can accept a lone pair of electrons whereas a base is a substance which can donate a lone pair of electrons.

$Cu{Cl}_2+4H_{2}O⟶{\left[Cu{\left(H_{2}O\right)}_4\right]}^{2+}+2{Cl}^{-}$

lewis acid base

$KI+4{SO}_2\left(s\right)⟶K^{+}\left[{\left({SO}_4\right)}_4{I}^{-}\right]$

lewis base acid

${BF}^3+{NH}_3⟶[H_{3}N\cdot {BF}_3]$

lewis acid-base

${SO}_3^{2-}+O⟶{SO}_4^{2-}$

lewis acid base