Which of the following are not rational?

\frac{2}{\sqrt{3}}

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\sqrt{16}

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π

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2 + \sqrt{25}

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Solution

The correct options are
B $π$
D $\frac{2}{\sqrt{3}}$
Only B and D are rational.
In A, $\sqrt{3}$ is not an Integer. hence, $\frac{2}{\sqrt{3}}$ it is not rational
In C, $π = 3.142..$ is a non terminating non recurring decimal. Hence it is not rational.

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Similar questions

\frac{3}{9}, \frac{- 4}{11}, \sqrt{2}, π

The rational number which is not lying between $\frac{5}{16}$ and $\frac{1}{2}$ is
$(a) \frac{3}{8}$

$(b) \frac{7}{16}$

$(c) \frac{1}{4}$

$(d) \frac{13}{32}$

\frac{3}{9}, \frac{- 4}{11}, \sqrt{2}, π

\frac{- 16}{20}

\frac{20}{- 25}

\frac{5}{16}

\frac{1}{2}

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