Which of the following are Pseudo Alums?
a) $N a_{2} S O_{4} . A l_{2} {(S O_{4})}_{3} .24 H_{2} O$
b) $M n S O_{4} . A l_{2} {(S O_{4})}_{3} .24 H_{2} O$
c) $F e S O_{4} . A l_{2} {(S O_{4})}_{3} .24 H_{2} O$
d) $K_{2} S O_{4} M n_{2} {(S O_{4})}_{3} .24 H_{2} O$

a, b only

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b, c only

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c, d only

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a, d only

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Solution

The correct option is B b, c only
Pseudo alums are formed by divalent cations. Here only option B and C contains alum with divalent cations. Thus option B and C are correct.

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Correct statements are

A. 'A' is tertiary alcohol B. 'B' contains a $3^{\circ}$ carbon

C. 'C' follows Huckel's rule D. both B and C are aromatic

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A) $A l_{4} C_{3}$ B) $B e_{2} C$ C) Ca $C_{2}$ D) $C H_{3} M g C l$

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Which of the following are Pseudo Alums?a) Na2SO4.Al2(SO4)3.24H2Ob) MnSO4.Al2(SO4)3.24H2Oc) FeSO4.Al2(SO4)3.24H2Od) K2SO4Mn2(SO4)3.24H2O

The correct option is B b, c onlyPseudo alums are formed by divalent cations. Here only option B and C contains alum with divalent cations. Thus option B and C are correct.

Which of the following are Pseudo Alums?
a) $N a_{2} S O_{4} . A l_{2} {(S O_{4})}_{3} .24 H_{2} O$
b) $M n S O_{4} . A l_{2} {(S O_{4})}_{3} .24 H_{2} O$
c) $F e S O_{4} . A l_{2} {(S O_{4})}_{3} .24 H_{2} O$
d) $K_{2} S O_{4} M n_{2} {(S O_{4})}_{3} .24 H_{2} O$

The correct option is B b, c only
Pseudo alums are formed by divalent cations. Here only option B and C contains alum with divalent cations. Thus option B and C are correct.