Which of the following numbers is divisible by both 6 and 8?

9638

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9640

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9642

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9648

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Solution

The correct option is D
9648

If a number is divisible by both 2 and 3, then it will be divisible by 6 also.

And a number will be divisible by 8 only if the last three digits are divisible by 8.

For 9648, it is divisible by both 2 and 3 and last 3 digits, i.e. 648 is divisible by 8

So, 9648 is divisible by both 8 and 6.

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Similar questions

9648 is divisible by both 6 and 8.

Which of the following statements are true?

(a) If a number is divisible by 3, it must be divisible by 9.

(b) If a number is divisible by 9, it must be divisible by 3.

(d) If a number is divisible by 9 and 10 both, then it must be divisible by 90.

(e) If two numbers are co-primes, at least one of them must be prime.

(f) All numbers which are divisible by 4 must also be divisible by 8.

(g) All numbers which are divisible by 8 must also be divisible by 4.

(h) If a number exactly divides two numbers separately, it must exactly divide their sum.

(i) If a number exactly divides the sum of two numbers, it must exactly divide the two numbers separately.

A number is divisible by both $5$ and $12$ . By which other number will that number be always divisible?

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