Which of the following are the intermediate in the reaction of excess methyl magnesium bromide with ethyl benzoate to make 2-phenyl-2-propanol?
$C_{6} H_{5} C O O C_{2} H_{5} + C H_{3} M g B r (e x c e s s) D i e t h y l e t h e r ⟶ H_{3} O^{+} ⟶$

I and II

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I and III

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II and III

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I, II, III

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Solution

The correct option is D I, II, III
As seen above, all the three intermediates are present in the reaction of excess methyl magnesium bromide with ethyl benzoate to make 2-phenyl-2-propanol.

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I I I

2,

I I I I

3,

I I

1,

I I - I I I I + I I I + I I I I I =

Which among the following compounds on reaction with methyl magnesium bromide followed by hydrolysis with water will give 2-methyl-2-propanol?

How are the following conversions carried out?

(i) Propene → Propan-2-ol

(ii) Benzyl chloride → Benzyl alcohol

(iii) Ethyl magnesium chloride → Propan-1-ol.

(iv) Methyl magnesium bromide → 2-Methylpropan-2-ol.

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