Which of the following arrangement does not represent the correct order of property stated against it ?

V^{2 +} < C r^{3 +} < M n^{2 +} < F e^{2 +}

: Paramagnetic behaviour

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N i^{2 +} < C o^{2 +} < F e^{2 +} < M n^{2 +}

Ionic size

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C o^{3 +} < F e^{3 +}, C r^{3 +} < S c^{3 +}

: Stability in aqueous solution

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S c < T i < C r < M n

: Number of oxidation states

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Solution

The correct option is B $V^{2 +} < C r^{3 +} < M n^{2 +} < F e^{2 +}$ : Paramagnetic behaviour
Paramagnetic property depends upon the number of unpaired electrons.
As the number of unpaired electrons unpaired electron increases, the paramagnetic property increases.
${F e}^{2 +} \Rightarrow n = 4 {M n}^{2 +} \Rightarrow n = 5$
$\Rightarrow {M n}^{2 +} > {F e}^{2 +}$ paramagnetic behaviour.

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Similar questions

V^{2 +} < C r^{2 +} < M n^{2} < F e^{2 +}

N i^{2 +} < C o^{2 +} < F e^{2 +} < M n^{2 +}

C o^{3 +} < F e^{3 +} < C r^{3 +} < S c^{3 +}

S c < T i < C r < M n

F e^{2 +}, F e^{3 +}, C r^{2 +}, C r^{3 +}, M n^{2 +}, M n^{3 +}

Write down the number of 3d electrons in each of the following ions:

Ti²⁺, V²⁺, Cr³⁺, Mn²⁺, Fe²⁺, Fe³⁺, CO²⁺, Ni²⁺ and Cu²⁺.

Indicate how would you expect the five 3d orbitals to be occupied for these hydrated ions (octahedral).

C r_{2} O_{7}^{2 -} + H^{+} + I^{-} \to C r^{3 +} + I_{2} + H_{2} O

C r_{2} O_{7}^{2 -} + F e_{2}^{+} + H^{+} \to C r^{3 +} + F e^{3 +} + H_{2} O

M n O^{4 -} + S O_{3}^{2 -} + H^{+} \to M n^{2 +} + S O_{4}^{2 -} + H_{2} O

M n O^{4 -} + H^{+} + B r^{-} \to M n^{2 +} + B r_{2} + H_{2} O

C u^{+}, F e^{2 +}, M n^{2 +}, C r^{3 +}, S c^{3 +}, T i^{4 +}

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