Which of the following arrangement of bond dissociation enthalpy of halogens is correct?
[1 Mark]

F - F > C l - C l > B r - B r

No worries! We‘ve got your back. Try BYJU‘S free classes today!

F - F < C l - C l < B r - B r

No worries! We‘ve got your back. Try BYJU‘S free classes today!

F - F > C l - C l < B r - B r

No worries! We‘ve got your back. Try BYJU‘S free classes today!

F - F < B r - B r < C l - C l

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $F - F < B r - B r < C l - C l$
Bond energy is inversely dependent on bond length. The order of bond length is $B r_{2} > C l_{2} > F_{2}$ .
Hence, the order of bond energy should $B r_{2} < C l_{2} < F_{2} .$ But bond dissociation enthalpy of $F_{2}$ is least because of small size of $F_{2}$ and large inter-electronic repulsions.
Thus, order of bond energy is $F - F < B r - B r < C l - C l$ .

Suggest Corrections

Similar questions

C - X

H - H

D - D

F - F

Join BYJU'S Learning Program