The correct options are
A Dilute H2SO4 with Pt electrodes
B Fused NaOH with inert electrodes
Dilute H2SO4 with Pt electrodes:
Here, as oxidation potential of OH− is greater than SO−24 so it will oxidise first and oxygen will be produced at anode.
Also, fused NaOH with inert electrodes:
Here, OH− oxidises at anode and oxygen produces at anode.