Which of the following arrangements is correct in respect to solubility in water?

C a S O_{4} > B a S O_{4} > B e S O_{4} > M g S O_{4} > S r S O_{4}

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B e S O_{4} > M g S O_{4} > C a S O_{4} > S r S O_{4} > B a S O_{4}

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B a S O_{4} > S r S O_{4} > C a s O_{4} > M g S O_{4} > B e S O_{4}

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B e S O_{4} > C a S O_{4} > M g S O_{4} > S r S O_{4} > B a S O_{4}

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Solution

The correct option is B $B e S O_{4} > M g S O_{4} > C a S O_{4} > S r S O_{4} > B a S O_{4}$
The correct order of solubility in water is $B e S O_{4} > M g S O_{4} > C a S O_{4} > S r S O_{4} > B a S O_{4}$
The increasing order of the ionic size is-
$B e^{2 +} < M g^{2 +} < C a^{2 +} < S r^{2 +} < B a^{2 +}$ .
The hydration energy decreases more rapidly than lattice energy, hence, solubility decreases down the group. (Hydration energy $\propto \frac{c h a r g e}{s i z e}$ ).

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