Question

Which of the following atomic orbitals does not participate in trigonal bipyramidal hybridisation i.e. $s{p}^{3}d$?

• A. $s$
• B. $d_{x^2-y^2}$
• C. $p_x$
• D. $p_y$

Answer 1

The correct option is B $d_{x^2-y^2}$

In trigonal bipyramidal hybridization $i.e.s{p}^{3}d$ there is the linear combination of $\text{one 4s−orbital with three}$ $\text{4p−orbitals}(4p_x,4p_y,\text{and}4p_z)\text{and one 3d−orbital}\left(3d_{z^2}\right)\text{results in five}s{p}^{3}d-\text{orbitals.}$

Option B is correct.