The correct option is C H2O2
H−12O2⟶H−22O+O02
H2O2 can be reduced to H2O as well as it can be oxidized to O2. Hence, it can act as an oxidizing agent by itself getting reduced to H2O as well as it can act as a reducing agent by getting oxidized to O2. Therefore, it can act as oxidizing as well as reducing agent.