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Hardness of Water and Treatment

Which of the ...

Question

Which of the following can be classified as a strong electrolyte?

{B r}_{2}

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C_{6} H_{12} O_{6}

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C a {C l}_{2}

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H_{2} O

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N O_{3}

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Solution

The correct option is E $C a {C l}_{2}$
Option C is the correct answer.
$C a C l_{2}$ in aqueous solution dissociates to give one $C a^{2 +}$ and two $C l^{-}$ ions.
Any substance which dissociates to form ions can be termed as an electrolyte.
Here Calcium Chloride gives one ion of Calcium and two Chloride ions. That is, from $C a C l_{2}$ a total of three ions are formed. Hence it can be classified as a strong electrolyte. The strong electrolytes dissociate completely in the solution. Here only $C a C l_{2}$ is the only compound which completely dissociates.

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Similar questions

C_{6} H_{12} O_{6}

H_{2} O

C_{6} H_{12} O_{6} + O_{2} \to C O_{2} + H_{2} O

C_{12} H_{22} O_{11} + H_{2} O I n v e r t a s e - ----- \to C_{6} H_{12} O_{6} A + C_{6} H_{12} O_{6} B

C_{6} H_{12} O_{6} z y m a s e - --- \to 2 C_{2} H_{5} O H + 2 {C O}_{2}

A

B

{Δ H}_{f}^{o}

C_{6} H_{12} O_{6} (s)

Δ H_{c o m b .}

C_{6} H_{12} O_{6} (s) = - 2816 k J {m o l}^{- 1}

{Δ H}_{f}^{o}

{C O}_{2} (g) = - 393.5 J {m o l}^{- 1}

{Δ H}_{f (H_{2} O)}^{o} = - 285.9 k J {m o l}^{- 1}

Δ H_{f}^{o}

C_{6} H_{12} O_{6} (s)

Δ H_{c o m b} [C_{6} H_{12} O_{6} (s)] = - 2816 k J / m o l

Δ H_{f}^{o}

{C O}_{2} (g) = - 393.5 k J / m o l

Δ H_{f}^{o}

H_{2} O (l) = - 285.9 k J / m o l

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