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Question

Which of the following can be oxidised by acidified K2Cr2O7?

A
Nitrate ions
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B
Sulphite ions
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C
Ferric ions
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D
Borate ions
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Solution

The correct option is A Sulphite ions
Cr2O27+3+4SO32+8H+2Cr3++3+6SO42+4H2O
K2Cr2O7 can oxidize sulphite ions (SO32) to SO42.
Nitrate ion, ferric ion, and borate ions are already in their highest oxidation state thus they cannot be further oxidized.

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