Which of the following can be the parametric equation of
$(x - 1)^{2} = - 36 (y - 4)$

$x = 1 + 18 t$ and $y = 4 - 9 t^{2}$

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$x = - 1 + 18 t$ and $y = - 4 - 9 t^{2}$

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$x = - 1 - 18 t$ and $y = 4 - 9 t^{2}$

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$x = 1 + 18 t$ and $y = - 4 - 9 t^{2}$

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Solution

The correct option is A
$x = 1 + 18 t$ and $y = 4 - 9 t^{2}$

The parametric equation of
$x^{2} = - 4 a y$ are $x = 2 a t$ and $y = - a t^{2}$

$\Rightarrow For (x - 1)^{2} = - 4 \times 9 (9 - 4)$ ,
it will be
$x - 1 = 2 \times 9 \times t and y - 4 = - 9 t^{2}$

$\Rightarrow x = 1 + 18 t$ and $y = 4 - 9 t^{2}$

Suggest Corrections

Similar questions

Which of the following can be the parametric equation of $x^{2} = 4 a y$

x^{2} - 4 x - 32 = - 12 y

(y - 2)^{2} = 12 (x - 4)

x^{2} + y^{2} = 4

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