The correct option is B OF2
(a) SiCl4+4H2O→Si(OH)4+4HCl (by SN2 mechanism)
Si has vacant d-orbitals which can accept lone pair from O atom in H2O to form bonds.
(b) OF2 hydrolyses in water but the reaction is very slow.
OF2+H2O→O2+2HF
(c) NCl3+3H2O→NH3+3HOCl
H2O attacks Cl which has vacant d-orbitals and not N
(d) SF4+2H2O→SO2+4HF
S has vacant d-orbitals which can accept lone pair from O atom in H2O to form bonds.