Which of the following cannot be hydrolysed?

S i C l_{4}

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O F_{2}

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N C l_{3}

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S F_{4}

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Solution

The correct option is B $O F_{2}$
(a) $S i C l_{4} + 4 H_{2} O \to S i (O H)_{4} + 4 H C l$ (by $S_{N} 2$ mechanism)
$S i$ has vacant d-orbitals which can accept lone pair from $O$ atom in $H_{2} O$ to form bonds.

(b) $O F_{2}$ hydrolyses in water but the reaction is very slow.
$O F_{2} + H_{2} O \to O_{2} + 2 H F$

(c) $N C l_{3} + 3 H_{2} O \to N H_{3} + 3 H O C l$
$H_{2} O$ attacks $C l$ which has vacant $d$ -orbitals and not $N$

(d) $S F_{4} + 2 H_{2} O \to S O_{2} + 4 H F$
$S$ has vacant d-orbitals which can accept lone pair from $O$ atom in $H_{2} O$ to form bonds.

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