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Question

Which of the following cannot exhibit hyperconjugation?

A
CH3˙CH2
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B
(CH3)2+CH
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C
CH3CH=CH2
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D
(CH3)3C+CH2
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Solution

The correct option is D (CH3)3C+CH2
Hyper conjugation is not shown by compounds which do not have hydrogen attached to adjacent carbon of sp2 carbon.
1381047_1097695_ans_10911f120126489f998b4553b32f315e.png

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