Which of the following cannot exhibit isomerism ?
(a) $C_{4} H_{10}$ (b) $C_{5} H_{12}$ (c) $C_{3} H_{8}$ (d) $C_{6} H_{14}$

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Solution

(c) $C_{3} H_{8}$
$C_{3} H_{8}$ is the compound which cannot exhibit isomerism, as it contains only 3 carbon atoms. Isomerism is possible only with hydrocarbons containing 4 or more carbon atoms.

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