The correct option is A I
The stability order of the carbanions can be determined using the −M effect of the substituents present at the para position. Higher the −M power of the substituents, higher will be the stability of the carbanion.
The order of −M power of the substituents is:
−NO2>−CN
−CH3 & −OCH3 shows +M effect which makes the carbanion less stable as compared to the carbanions where −M group is attached
Therefore, carbanion I is the most stable