Which of the following carbon-halogen bond is extremely polar though nonionic among given alkyl halides?

C - F

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C - B r

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C - C l

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C - I

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Solution

The correct option is A $C - F$
$C - F$ bond is extremely polar because Flourine is most Electronegative atom (E.N = 4.0) so the E.N difference is more for carbon and Flourine.
Polarity order : $C - F > C - B r > C - C l > C - I$

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Similar questions

Q. Arrange the following bonds according to their average bond energies in descending order:

C - C l, C - B r, C - F, C - I

Q. Consider following three halides:
(I)

C H_{3} - C H_{2} - C l

;
(II)

C H_{2} = C H - C l

;
(III)

C_{6} H_{5} C l

Arrange

C - C l

bond length of these compounds in decreasing order.

Among halogens, the correct order of amount of energy released in electron gain (electron gain enthalpy ) is
(a) F > Cl > Br > I (b) F < Cl < Br < I (c) F < Cl > Br > I (d) F < Cl < Br < I

Which of the following alkyl halides will undergo $S_{N} 1$ reaction most readily?

(a) $(C H_{3})_{3} C - F$ (b) $(C H_{3})_{3} C - C l$ (c) $(C H_{3})_{3} C - B r$ (d) $(C H_{3})_{3} C - I$

Q. Arrange the following bonds according to their average bond energies in descending order:

C - C l, C - B r, C - F, C - I

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Which of the following carbon-halogen bond is extremely polar though nonionic among given alkyl halides?

The correct option is A C−FC−F bond is extremely polar because Flourine is most Electronegative atom (E.N = 4.0) so the E.N difference is more for carbon and Flourine.Polarity order : C−F>C−Br>C−Cl>C−I

The correct option is A $C - F$
$C - F$ bond is extremely polar because Flourine is most Electronegative atom (E.N = 4.0) so the E.N difference is more for carbon and Flourine.
Polarity order : $C - F > C - B r > C - C l > C - I$