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Question

Which of the following cations (i.e., basic radicals) forms colored (not white) precipitate with aqueous solution of potassium iodide but the precipitate does not dissolve in excess of reagent ?

A
Hg2+
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B
Hg2+2
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C
Bi3+
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D
Cu2+
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Solution

The correct option is C Hg2+2
Option (B) is correct.

(a) Hg2++2IHgI2(red/scarlet)
HgI2+2I[HgI4]2(solublecomplex)

(b) Hg2+2+2IHg2I2(green)
Hg2I2+2I[HgI4]2+Hg(black)

(c) Bi3++3IBiI3(black)
BiI3+I[BiI4](orangecolorsolublecomplex)

(d) 2Cu2++5I2CuI(white)+I3

Therefore, we can see that in option B, the precipitate is not soluble in excess of the reagent and remain as black Mercury precipitate

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