The correct option is C Cd(s)|Cd2+(aq)(0.01M)||H+(pH=1)|H2(g)(1atm),Pt
Zn(s)+2H+→Zn2++H2(g)
0.1M 0.02M 0.5atm
Ecell=E∘cell−0.05912log0.02×0.5(0.1)2=E∘cell
Cu(s)+2Ag+→Cu2++Ag(s)
0.5M 0.25M
Ecell=E∘cell−0.05912log0.25(0.5)2=E∘cell
Cd(s)+2H+→Cd2++H2(g)
0.1M 0.01M 1atm
Ecell=E∘cell−0.05912log0.01(0.1)2=E∘cell
Zn(s)+2H+→Zn2++H2(g)
0.1M 0.1M 1atm
Ecell=E∘cell−0.05912log0.1(0.1)2≠E∘cell