Which of the following change is neither oxidation nor reduction?

K_{2} C r_{2} O_{7}

K_{2} C r O_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N a_{2} S O_{4}

N a H S O_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C u C l_{2}

C u S O_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

All the above

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C All the above
$K_{2} C r_{2}^{+ 6} O_{7} \to K_{2} C r^{+ 6} O_{4}$
$N a^{1 +}$ $\to$ $N a^{1 +}$
$C u^{2 +}$ $\to$ $C u^{2 +}$
Therefore, all the above are not redox reactions.

Suggest Corrections

Similar questions

When $K_{2} C r_{2} O_{7}$ is converted to $K_{2} C r O_{4}$ the change in the oxidation state of chromium is

H C l O_{3}

H C l O_{4}

{N H}_{4}^{+}

N H_{3}

N O_{2}

N_{2} O_{4}

H S O_{3}^{-}

S O_{4}^{2 -}

H_{2} O_{2}

H_{2} O

Join BYJU'S Learning Program