Which of the following changes require reducing agent?

C r O_{4}^{2 -} \to C r_{2} O_{7}^{2 -}

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B r O_{3}^{-} \to B r O^{-}

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H_{2} A O_{3} \to H A s O_{4}^{2 -}

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A l (O H)_{3} \to A l {(O H)}_{4}^{-}

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Solution

The correct option is A $B r O_{3}^{-} \to B r O^{-}$
A. In ${C r O}_{4}^{2 -} & {C r}_{2} O_{7}^{2 -}$ the oxidation state in both the cases for $C r$ is +6. So, no reducing agent is required.

B. In ${B r O}_{3}^{-} & {B r O}^{-}$ , the oxidation state of $B r$ changes from +5 to +1. So, it requires a reducing agent.

C. In $H_{2} {A s O}_{3} & {H A s O}_{4}^{2 -}$ , the oxidation state of $A s$ changes from +4 to +5. So, it requires an oxidizing agent.

D. In ${A l (O H)}_{3} & {A l (O H)}_{4}^{-}$ , the oxidation state of $A l$ is +3 in both cases. So, no reducing agent is required.
So, correct answer is option B.

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