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Question

Which of the following complex compounds will exhibit highest paramagnetic behaviour?

(At. No. : Ti=22,Cr=24,Co=27,Zn=30)

A
[Ti(NH3)6]3+
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B
[Cr(NH3)6]3+
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C
[Co(NH3)6]3+
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D
[Zn(NH3)6]2+
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Solution

The correct option is B [Cr(NH3)6]3+
(A) [Ti(NH3)6]3+: Ti has 3d1 configuration and thus has one unpaired electron.

(B) [Cr(NH3)6]3+: The complex is inner orbital complex but 3d3 configuration has three unpaired electrons with weak as well as with strong field ligand.

(C) [Co(NH3)6]3+: The cobalt ion is in +3 oxidation state with 3d6 configuration and thus is diamagnetic octahedral complex, [Co(NH3)6]3+, as the electrons paired up.

(D) [Zn(NH3)6]2+: Because of 3d10 configuration no (n1)d orbital is available for d2sp3 hybridisation and thus forms outer orbital complex. The complex is diamagnetic.


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