Question

Which of the following complex ion possesses $s{p}^3{d}^2$ hybridization ?

• A. ${\left[Cr{\left(N{H}_3\right)}_6\right]}^{3+}$
• B. ${\left[Fe{F}_6\right]}^{3-}$
• C. ${\left[Co{\left(N{O}_2\right)}_6\right]}^{3-}$
• D. ${\left[Ti{F}_6\right]}^{3-}$

Answer 1

The correct option is B ${\left[Fe{F}_6\right]}^{3-}$

Option (B) is correct.

${\left[Fe{F}_6\right]}^{3-}$ complex ion possesses $s{p}^3{d}^2$ hybridization.

The electronic configurations of $Cr,Fe,Co$ and $Ti$ in the complexes are ${\left(3d\right)}^3$, ${\left(3d\right)}^5$, ${\left(3d\right)}^6$ and ${\left(3d\right)}^1$, respectively.

These involve $d^{2}s{p}^3,s{p}^3{d}^2,d^{2}s{p}^3$ and $d^{2}s{p}^3$ hybridization respectively.