Which of the following complex ions absorbs the light of minimum wavelength?

{[C o {(H_{2} O)}_{6}]}^{3 +}

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{[C o F_{6}]}^{3 -}

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{[C o {(C N)}_{6}]}^{3 -}

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{[C o {({N H}_{3})}_{6}]}^{3 +}

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Solution

The correct option is D ${[C o {(C N)}_{6}]}^{3 -}$
Wavelength of light absorbed $\propto \frac{1}{s t b i l i t y o f c o m p l e x}$
In all given complexes Co is present in $+ 3$ state and among the given ligands ${(C N)}^{-}$ is the strongest ligand. Hence ${[C o {(C N)}_{6}]}^{3 -}$ is most stable, thus it absorbs light of minimum wavelength. Thus answer is option C

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Similar questions

The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light in the visible region, for the complexes, $[C o (N H_{3})_{6}]^{3 +}, [C o (C N)_{6}]^{3 -}, [C o (H_{2} O)_{6}]^{3 +}$
$[C o (N H_{3})_{6}]^{3 +}, [C o (C N)_{6}]^{3 -}, [C o (H_{2} O)_{6}]^{3 +}$
(a) $[C o (C N)_{6}]^{3 -} > [C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +}$
(b) $[C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +} > [C o (N H_{3})_{6}]^{3 +}$
(c) $[C o (H_{2} O)_{6}]^{3 +} > [C o (N H_{3})_{6}]^{3 +} > [C o (C N)_{6}]^{3 -}$
(d) $[C o (C N)_{6}]^{3 -} > [C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +}$

Q. Identify the correct order of wavelength of light absorbed for the following complex ions.

[C o (H_{2} O)_{6}]^{3 +}; C o (C N)_{6}]^{3 -}; [C o (I)_{6}]^{3 -}; [C o (e n)_{3}]^{3 +}

I II III IV

Q. The correct increasing order of wavelengths of absorption in the visible region for the complexes of

C o^{3 +}

is:

Q. Correct increasing order for the wavelength of absorbtion in the visible region for the complexes of

C o^{3 +}

is:

Correct increasing order for the wavelengths of absorption in the visible region for the complexes of $C o^{3 +}$ is

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