Question

Which of the following complex is optically inactive?

• A. $\left[Pd\right(en{)}_2\left(C{l}_2\right]$
• B. $\left[RhCl\right(CO\left)\right(PP{h}_3\left)\right(N{H}_3\left)\right]$
  
• C. $\left[Fe\right(en{)}_{2}C{l}_2]$
• D. $\left[Fe\right(C_2{O}_4{)}_3{]}^{3-}$

Answer 1

The correct option is B $\left[RhCl\right(CO\left)\right(PP{h}_3\left)\right(N{H}_3\left)\right]$


$\left[RhCl\right(CO\left)\right(PP{h}_3\left)\right(N{H}_3\left)\right]$ is inactive as it is square planar complex. It will have a plane of symmetry in the molecule.

Cis forms of $Fe\left(en{)}_{2}C{l}_2\right]$ and $\left[Pd\right(en{)}_2\left(C{l}_2\right]$ are optically active since they wont have symmetry.

$\left[Fe\right(C_2{O}_4{)}_3{]}^{3-}$ is also optically active sue to absence of symmtery.

Hence, option (a) is correct.